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    Math Deficiency – II
    MD-002
    Progress0 / 32 topics
    Topics
    1. Complex Numbers2. Arithmetic with Complex Numbers (Add, subtract, multiply and divide complex numbers)3. Trigonometric Polar Form of Complex Numbers4. De Moivre's Theorem and nth Roots5. Recursion6. Sequences and Series7. Sigma Notation8. Arithmetic Series9. Geometric Series (Sum infinite and finite geometric series and categorize geometric series)10. Counting with Permutations and Combinations11. Basic Probability12. Binomial Theorem13. Limit: Notation, Graphs to Find Limits, Tables to Find Limits14. Substitution to Find Limits, Rationalization to Find Limits15. One Sided Limits and Continuity16. Rate of Change: Instantaneous Rate of Change17. Tangent Lines and Rates of Change18. Derivatives: The Derivative Function19. Introduction to Techniques of Differentiation20. The Product and Quotient Rules21. Derivatives of Trigonometric Functions22. The Chain Rule23. Derivatives of Logarithmic Functions24. Derivatives of Exponential and Inverse Trigonometric Functions25. Increase, Decrease, and Concavity26. Relative Extrema, Absolute Maxima and Minima27. Integrals: An Overview of the Area Problem28. Area Under a Curve29. The Indefinite Integral30. Integration by Substitution31. The Definition of Area as a Limit; Sigma Notation32. The Definite Integral
    MD-002›Derivatives of Trigonometric Functions
    Math Deficiency – IITopic 21 of 32

    Derivatives of Trigonometric Functions

    8 minread
    1,317words
    Intermediatelevel

    Derivatives of Trigonometric Functions

    In calculus, the derivatives of trigonometric functions are fundamental. These derivatives allow us to analyze the rates of change of various periodic and oscillatory phenomena, which are common in physics, engineering, and many other fields. Below are the key trigonometric functions and their derivatives:


    1. Derivative of Sine Function:

    ddx(sin⁡(x))=cos⁡(x)\frac{d}{dx}(\sin(x)) = \cos(x)dxd​(sin(x))=cos(x)

    Explanation:

    • The derivative of the sine function sin⁡(x)\sin(x)sin(x) is the cosine function cos⁡(x)\cos(x)cos(x). This result shows that the rate of change of the sine wave is given by the value of the cosine wave.
    • The sine function is a periodic function, and its rate of change oscillates in a way that is represented by the cosine function.

    2. Derivative of Cosine Function:

    ddx(cos⁡(x))=−sin⁡(x)\frac{d}{dx}(\cos(x)) = -\sin(x)dxd​(cos(x))=−sin(x)

    Explanation:

    • The derivative of the cosine function cos⁡(x)\cos(x)cos(x) is the negative sine function −sin⁡(x)-\sin(x)−sin(x). This result shows that the rate of change of the cosine function is in the opposite direction of the sine function.
    • The negative sign indicates that as the cosine function increases, the sine function decreases, and vice versa.

    3. Derivative of Tangent Function:

    ddx(tan⁡(x))=sec⁡2(x)\frac{d}{dx}(\tan(x)) = \sec^2(x)dxd​(tan(x))=sec2(x)

    Explanation:

    • The derivative of the tangent function tan⁡(x)\tan(x)tan(x) is sec⁡2(x)\sec^2(x)sec2(x), which is the square of the secant function.
    • The tangent function has vertical asymptotes where the cosine function equals zero, which is why its derivative involves the secant squared function, as it becomes undefined where the cosine function is zero (where tangent has vertical asymptotes).

    4. Derivative of Cotangent Function:

    ddx(cot⁡(x))=−csc⁡2(x)\frac{d}{dx}(\cot(x)) = -\csc^2(x)dxd​(cot(x))=−csc2(x)

    Explanation:

    • The derivative of the cotangent function cot⁡(x)\cot(x)cot(x) is −csc⁡2(x)-\csc^2(x)−csc2(x), which is the negative square of the cosecant function.
    • Just like the tangent function, the cotangent function has vertical asymptotes where the sine function equals zero, and its derivative involves the cosecant squared function.

    5. Derivative of Secant Function:

    ddx(sec⁡(x))=sec⁡(x)⋅tan⁡(x)\frac{d}{dx}(\sec(x)) = \sec(x) \cdot \tan(x)dxd​(sec(x))=sec(x)⋅tan(x)

    Explanation:

    • The derivative of the secant function sec⁡(x)\sec(x)sec(x) is sec⁡(x)⋅tan⁡(x)\sec(x) \cdot \tan(x)sec(x)⋅tan(x), which is the secant function multiplied by the tangent function.
    • This derivative shows how the secant function changes with respect to xxx. Since the secant function is related to the cosine function, this derivative indicates the relationship between the secant, cosine, and tangent functions.

    6. Derivative of Cosecant Function:

    ddx(csc⁡(x))=−csc⁡(x)⋅cot⁡(x)\frac{d}{dx}(\csc(x)) = -\csc(x) \cdot \cot(x)dxd​(csc(x))=−csc(x)⋅cot(x)

    Explanation:

    • The derivative of the cosecant function csc⁡(x)\csc(x)csc(x) is −csc⁡(x)⋅cot⁡(x)-\csc(x) \cdot \cot(x)−csc(x)⋅cot(x), which is the negative cosecant function multiplied by the cotangent function.
    • The cosecant function is the reciprocal of the sine function, and its derivative shows the relationship between the cosecant and cotangent functions.

    Summary of Derivatives of Trigonometric Functions

    Function Derivative
    sin⁡(x)\sin(x)sin(x) cos⁡(x)\cos(x)cos(x)
    cos⁡(x)\cos(x)cos(x) −sin⁡(x)-\sin(x)−sin(x)
    tan⁡(x)\tan(x)tan(x) sec⁡2(x)\sec^2(x)sec2(x)
    cot⁡(x)\cot(x)cot(x) −csc⁡2(x)-\csc^2(x)−csc2(x)
    sec⁡(x)\sec(x)sec(x) sec⁡(x)⋅tan⁡(x)\sec(x) \cdot \tan(x)sec(x)⋅tan(x)
    csc⁡(x)\csc(x)csc(x) −csc⁡(x)⋅cot⁡(x)-\csc(x) \cdot \cot(x)−csc(x)⋅cot(x)

    Important Notes:

    • These derivatives hold for functions of the form sin⁡(x)\sin(x)sin(x), cos⁡(x)\cos(x)cos(x), tan⁡(x)\tan(x)tan(x), etc. If these functions are composed with other functions (e.g., sin⁡(2x)\sin(2x)sin(2x) or cos⁡(3x+5)\cos(3x + 5)cos(3x+5)), you must use the Chain Rule.
    • Trigonometric functions are periodic, and their derivatives are also periodic. Understanding these derivatives allows us to analyze oscillating functions, which are common in physics and engineering.

    Example Problems

    1. Example 1: Differentiate f(x)=3sin⁡(x)+2cos⁡(x)f(x) = 3\sin(x) + 2\cos(x)f(x)=3sin(x)+2cos(x)

      Using the basic derivative rules:

      f′(x)=3cos⁡(x)−2sin⁡(x)f'(x) = 3\cos(x) - 2\sin(x)f′(x)=3cos(x)−2sin(x)
    2. Example 2: Differentiate g(x)=tan⁡(2x)g(x) = \tan(2x)g(x)=tan(2x)

      Here, you apply the chain rule. The derivative of tan⁡(x)\tan(x)tan(x) is sec⁡2(x)\sec^2(x)sec2(x), but because of the inner function 2x2x2x, you also need to multiply by the derivative of 2x2x2x, which is 2:

      g′(x)=2⋅sec⁡2(2x)g'(x) = 2 \cdot \sec^2(2x)g′(x)=2⋅sec2(2x)

    Conclusion

    The derivatives of trigonometric functions form the basis for solving many problems in calculus, especially those involving oscillations, waves, and periodic phenomena. Recognizing these derivatives and applying the chain rule when necessary allows you to handle more complex expressions involving trigonometric functions effectively.

    Previous topic 20
    The Product and Quotient Rules
    Next topic 22
    The Chain Rule

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