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    MD-002

    Math Deficiency – II

    Progress0 / 32 done
    Topics32
    1Complex Numbers2Arithmetic with Complex Numbers (Add, subtract, multiply and divide complex numbers)3Trigonometric Polar Form of Complex Numbers4De Moivre's Theorem and nth Roots5Recursion6Sequences and Series7Sigma Notation8Arithmetic Series9Geometric Series (Sum infinite and finite geometric series and categorize geometric series)10Counting with Permutations and Combinations11Basic Probability12Binomial Theorem
    13Notation, Graphs to Find Limits, Tables to Find Limits14Substitution to Find Limits, Rationalization to Find Limits15One Sided Limits and Continuity
    16Instantaneous Rate of Change17Tangent Lines and Rates of Change
    18The Derivative Function19Introduction to Techniques of Differentiation20The Product and Quotient Rules21Derivatives of Trigonometric Functions22The Chain Rule23Derivatives of Logarithmic Functions24Derivatives of Exponential and Inverse Trigonometric Functions25Increase, Decrease, and Concavity26Relative Extrema, Absolute Maxima and Minima
    27An Overview of the Area Problem28Area Under a Curve29The Indefinite Integral30Integration by Substitution31The Definition of Area as a Limit; Sigma Notation32The Definite Integral
    11 min read
    Topic 12 of 32
    Topic Study Note Illustration
    12

    Binomial Theorem

    The Binomial Theorem provides a way to expand expressions that are raised to a power. Specifically, it expands expressions of the form ( a + b )...

    Binomial Theorem

    The Binomial Theorem provides a way to expand expressions that are raised to a power. Specifically, it expands expressions of the form (a+b)n(a + b)^n(a+b)n, where aaa and bbb are any numbers (or variables), and nnn is a positive integer.

    The theorem states that:

    (a+b)n=∑k=0n(nk)an−kbk(a + b)^n = \sum_{k=0}^{n} \binom{n}{k} a^{n-k} b^k(a+b)n=k=0∑n​(kn​)an−kbk

    Where:

    • (nk)\binom{n}{k}(kn​) is the binomial coefficient, which represents the number of ways to choose kkk objects from nnn objects. It is calculated as:
    (nk)=n!k!(n−k)!\binom{n}{k} = \frac{n!}{k!(n-k)!}(kn​)=k!(n−k)!n!​
    • aaa and bbb are the two terms in the binomial expression.
    • nnn is the exponent to which the binomial is raised.
    • kkk is the index that runs from 000 to nnn in the sum.

    Expanded Form of the Binomial Theorem

    The Binomial Theorem essentially expresses the expansion of (a+b)n(a + b)^n(a+b)n as a sum of terms where:

    • The first term is ana^{n}an,
    • The second term is an−1ba^{n-1}ban−1b,
    • The third term is an−2b2a^{n-2}b^2an−2b2, and so on,
    • The last term is bnb^nbn.

    Each term in the expansion involves:

    • A binomial coefficient (nk)\binom{n}{k}(kn​),
    • Powers of aaa and bbb, with aaa starting at the highest power and decreasing, while bbb starts at the lowest power and increases.

    Example 1: Expanding (a+b)3(a + b)^3(a+b)3

    We can apply the Binomial Theorem to expand (a+b)3(a + b)^3(a+b)3.

    1. Using the formula:
    (a+b)3=∑k=03(3k)a3−kbk(a + b)^3 = \sum_{k=0}^{3} \binom{3}{k} a^{3-k} b^k(a+b)3=k=0∑3​(k3​)a3−kbk

    This gives the following terms:

    • For k=0k = 0k=0: (30)a3−0b0=1⋅a3⋅1=a3\binom{3}{0} a^{3-0} b^0 = 1 \cdot a^3 \cdot 1 = a^3(03​)a3−0b0=1⋅a3⋅1=a3,
    • For k=1k = 1k=1: (31)a3−1b1=3⋅a2⋅b=3a2b\binom{3}{1} a^{3-1} b^1 = 3 \cdot a^2 \cdot b = 3a^2b(13​)a3−1b1=3⋅a2⋅b=3a2b,
    • For k=2k = 2k=2: (32)a3−2b2=3⋅a1⋅b2=3ab2\binom{3}{2} a^{3-2} b^2 = 3 \cdot a^1 \cdot b^2 = 3ab^2(23​)a3−2b2=3⋅a1⋅b2=3ab2,
    • For k=3k = 3k=3: (33)a3−3b3=1⋅a0⋅b3=b3\binom{3}{3} a^{3-3} b^3 = 1 \cdot a^0 \cdot b^3 = b^3(33​)a3−3b3=1⋅a0⋅b3=b3.
    1. Thus, the expanded form is:
    (a+b)3=a3+3a2b+3ab2+b3(a + b)^3 = a^3 + 3a^2b + 3ab^2 + b^3(a+b)3=a3+3a2b+3ab2+b3

    Example 2: Expanding (x+2)4(x + 2)^4(x+2)4

    Now, let's expand (x+2)4(x + 2)^4(x+2)4.

    1. Using the Binomial Theorem:
    (x+2)4=∑k=04(4k)x4−k2k(x + 2)^4 = \sum_{k=0}^{4} \binom{4}{k} x^{4-k} 2^k(x+2)4=k=0∑4​(k4​)x4−k2k

    This gives the following terms:

    • For k=0k = 0k=0: (40)x4−020=1⋅x4⋅1=x4\binom{4}{0} x^{4-0} 2^0 = 1 \cdot x^4 \cdot 1 = x^4(04​)x4−020=1⋅x4⋅1=x4,
    • For k=1k = 1k=1: (41)x4−121=4⋅x3⋅2=8x3\binom{4}{1} x^{4-1} 2^1 = 4 \cdot x^3 \cdot 2 = 8x^3(14​)x4−121=4⋅x3⋅2=8x3,
    • For k=2k = 2k=2: (42)x4−222=6⋅x2⋅4=24x2\binom{4}{2} x^{4-2} 2^2 = 6 \cdot x^2 \cdot 4 = 24x^2(24​)x4−222=6⋅x2⋅4=24x2,
    • For k=3k = 3k=3: (43)x4−323=4⋅x⋅8=32x\binom{4}{3} x^{4-3} 2^3 = 4 \cdot x \cdot 8 = 32x(34​)x4−323=4⋅x⋅8=32x,
    • For k=4k = 4k=4: (44)x4−424=1⋅x0⋅16=16\binom{4}{4} x^{4-4} 2^4 = 1 \cdot x^0 \cdot 16 = 16(44​)x4−424=1⋅x0⋅16=16.
    1. Thus, the expanded form is:
    (x+2)4=x4+8x3+24x2+32x+16(x + 2)^4 = x^4 + 8x^3 + 24x^2 + 32x + 16(x+2)4=x4+8x3+24x2+32x+16

    Binomial Coefficients

    The binomial coefficients (nk)\binom{n}{k}(kn​) can be computed using the formula:

    (nk)=n!k!(n−k)!\binom{n}{k} = \frac{n!}{k!(n-k)!}(kn​)=k!(n−k)!n!​

    Where:

    • n!n!n! represents the factorial of nnn,
    • k!k!k! represents the factorial of kkk,
    • (n−k)!(n-k)!(n−k)! represents the factorial of (n−k)(n-k)(n−k).

    These coefficients are also known as Pascal's Triangle entries. Pascal’s Triangle is a triangular array where the nnn-th row corresponds to the coefficients of the expansion of (a+b)n(a + b)^n(a+b)n. For example, the first few rows of Pascal's Triangle look like this:

    111121133114641\begin{array}{ccccccc} 1 & & & & & & \\ 1 & 1 & & & & & \\ 1 & 2 & 1 & & & & \\ 1 & 3 & 3 & 1 & & & \\ 1 & 4 & 6 & 4 & 1 & & \\ \end{array}11111​1234​136​14​1​​​

    So, the coefficients for the expansion of (a+b)4(a + b)^4(a+b)4 are 1,4,6,4,11, 4, 6, 4, 11,4,6,4,1, which correspond to the entries in the 4th row of Pascal’s Triangle.

    Special Cases and Applications

    1. Squaring a Binomial: The Binomial Theorem can be used to expand powers of binomials like (a+b)2(a + b)^2(a+b)2. For example:

      (a+b)2=a2+2ab+b2(a + b)^2 = a^2 + 2ab + b^2(a+b)2=a2+2ab+b2

      This is just a special case of the general formula where n=2n = 2n=2.

    2. Cube of a Binomial: Similarly, for cubing a binomial:

      (a+b)3=a3+3a2b+3ab2+b3(a + b)^3 = a^3 + 3a^2b + 3ab^2 + b^3(a+b)3=a3+3a2b+3ab2+b3
    3. General Power Expansion: For higher powers like (a+b)n(a + b)^n(a+b)n, the Binomial Theorem allows for the efficient computation of the expansion without multiplying out terms individually.

    Summary

    • The Binomial Theorem allows you to expand expressions of the form (a+b)n(a + b)^n(a+b)n, where aaa and bbb are terms, and nnn is a positive integer.
    • The expansion involves binomial coefficients (nk)\binom{n}{k}(kn​), which can be computed using factorials, and the terms an−kbka^{n-k} b^kan−kbk.
    • The binomial coefficients follow a pattern known as Pascal's Triangle.
    • The Binomial Theorem is widely used in algebra, calculus, probability theory, and many other areas of mathematics for simplifying the expansion of binomial expressions.
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