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    Math Deficiency – II
    MD-002
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    Topics
    1. Complex Numbers2. Arithmetic with Complex Numbers (Add, subtract, multiply and divide complex numbers)3. Trigonometric Polar Form of Complex Numbers4. De Moivre's Theorem and nth Roots5. Recursion6. Sequences and Series7. Sigma Notation8. Arithmetic Series9. Geometric Series (Sum infinite and finite geometric series and categorize geometric series)10. Counting with Permutations and Combinations11. Basic Probability12. Binomial Theorem13. Limit: Notation, Graphs to Find Limits, Tables to Find Limits14. Substitution to Find Limits, Rationalization to Find Limits15. One Sided Limits and Continuity16. Rate of Change: Instantaneous Rate of Change17. Tangent Lines and Rates of Change18. Derivatives: The Derivative Function19. Introduction to Techniques of Differentiation20. The Product and Quotient Rules21. Derivatives of Trigonometric Functions22. The Chain Rule23. Derivatives of Logarithmic Functions24. Derivatives of Exponential and Inverse Trigonometric Functions25. Increase, Decrease, and Concavity26. Relative Extrema, Absolute Maxima and Minima27. Integrals: An Overview of the Area Problem28. Area Under a Curve29. The Indefinite Integral30. Integration by Substitution31. The Definition of Area as a Limit; Sigma Notation32. The Definite Integral
    MD-002›Geometric Series (Sum infinite and finite geometric series and categorize geometric series)
    Math Deficiency – IITopic 9 of 32

    Geometric Series (Sum infinite and finite geometric series and categorize geometric series)

    10 minread
    1,653words
    Intermediatelevel

    Geometric Series

    A geometric series is the sum of the terms in a geometric sequence, where each term after the first is found by multiplying the previous term by a constant called the common ratio. The general form of a geometric sequence is:

    a,ar,ar2,ar3,ar4,…a, ar, ar^2, ar^3, ar^4, \ldotsa,ar,ar2,ar3,ar4,…

    Where:

    • aaa is the first term.
    • rrr is the common ratio (the factor by which each term is multiplied to get the next term).
    • nnn is the number of terms.

    Geometric Series:

    A geometric series is the sum of the terms in a geometric sequence. If we sum the first nnn terms of a geometric sequence, the result is a finite geometric series. The formula for the sum of the first nnn terms of a finite geometric series is:

    Sn=a(1−rn)1−rforr≠1S_n = \frac{a(1 - r^n)}{1 - r} \quad \text{for} \quad r \neq 1Sn​=1−ra(1−rn)​forr=1

    Where:

    • SnS_nSn​ is the sum of the first nnn terms.
    • aaa is the first term.
    • rrr is the common ratio.
    • nnn is the number of terms.

    Infinite Geometric Series:

    An infinite geometric series is the sum of the terms in a geometric sequence that goes on indefinitely. The sum of an infinite geometric series is only finite (i.e., converges) when the absolute value of the common ratio ∣r∣|r|∣r∣ is less than 1. In such cases, the sum of the infinite series is:

    S∞=a1−rfor∣r∣<1S_{\infty} = \frac{a}{1 - r} \quad \text{for} \quad |r| < 1S∞​=1−ra​for∣r∣<1

    If ∣r∣≥1|r| \geq 1∣r∣≥1, the series diverges and does not have a finite sum.

    Key Categories of Geometric Series:

    1. Finite Geometric Series: A finite geometric series is the sum of the first nnn terms of a geometric sequence. The formula to find the sum of a finite geometric series is:

      Sn=a(1−rn)1−r,forr≠1S_n = \frac{a(1 - r^n)}{1 - r}, \quad \text{for} \quad r \neq 1Sn​=1−ra(1−rn)​,forr=1

      Example: Find the sum of the first 4 terms of the geometric series with the first term a=3a = 3a=3 and the common ratio r=2r = 2r=2.

      The series is:

      3,6,12,24,…3, 6, 12, 24, \ldots3,6,12,24,…

      Using the formula for the sum of a finite geometric series:

      S4=3(1−24)1−2=3(1−16)−1=3(−15)−1=45S_4 = \frac{3(1 - 2^4)}{1 - 2} = \frac{3(1 - 16)}{-1} = \frac{3(-15)}{-1} = 45S4​=1−23(1−24)​=−13(1−16)​=−13(−15)​=45

      So, the sum of the first 4 terms is 45.

    2. Infinite Geometric Series: An infinite geometric series is the sum of an infinite number of terms. The sum converges if the absolute value of the common ratio ∣r∣|r|∣r∣ is less than 1. The formula for the sum of an infinite geometric series is:

      S∞=a1−r,for∣r∣<1S_{\infty} = \frac{a}{1 - r}, \quad \text{for} \quad |r| < 1S∞​=1−ra​,for∣r∣<1

      Example: Find the sum of the infinite geometric series where a=5a = 5a=5 and r=12r = \frac{1}{2}r=21​.

      The series is:

      5,52,54,58,…5, \frac{5}{2}, \frac{5}{4}, \frac{5}{8}, \ldots5,25​,45​,85​,…

      Using the formula for the sum of an infinite geometric series:

      S∞=51−12=512=10S_{\infty} = \frac{5}{1 - \frac{1}{2}} = \frac{5}{\frac{1}{2}} = 10S∞​=1−21​5​=21​5​=10

      So, the sum of the infinite geometric series is 10.

    Geometric Series Convergence and Divergence:

    1. Convergent Infinite Geometric Series: When ∣r∣<1|r| < 1∣r∣<1, the infinite geometric series converges to a finite sum. This means that the sum of the series approaches a finite value as the number of terms increases.

    2. Divergent Infinite Geometric Series: When ∣r∣≥1|r| \geq 1∣r∣≥1, the infinite geometric series diverges. This means that the sum grows without bound as more terms are added.

      • If r=1r = 1r=1, each term in the series is equal to aaa, so the sum is just a+a+a+…a + a + a + \ldotsa+a+a+…, which grows indefinitely.
      • If ∣r∣>1|r| > 1∣r∣>1, the terms get larger in magnitude, and the sum grows without bound.

    Examples:

    Example 1: Finite Geometric Series

    Find the sum of the first 6 terms of the geometric series with a=4a = 4a=4 and r=13r = \frac{1}{3}r=31​.

    The series is:

    4,43,49,427,481,4243,…4, \frac{4}{3}, \frac{4}{9}, \frac{4}{27}, \frac{4}{81}, \frac{4}{243}, \ldots4,34​,94​,274​,814​,2434​,…

    Using the formula for the sum of a finite geometric series:

    S6=4(1−(13)6)1−13=4(1−1729)23=4(728729)23=4×728729×32=29121458≈2S_6 = \frac{4(1 - (\frac{1}{3})^6)}{1 - \frac{1}{3}} = \frac{4(1 - \frac{1}{729})}{\frac{2}{3}} = \frac{4(\frac{728}{729})}{\frac{2}{3}} = \frac{4 \times 728}{729} \times \frac{3}{2} = \frac{2912}{1458} \approx 2S6​=1−31​4(1−(31​)6)​=32​4(1−7291​)​=32​4(729728​)​=7294×728​×23​=14582912​≈2

    So, the sum of the first 6 terms is approximately 2.

    Example 2: Infinite Geometric Series

    Find the sum of the infinite geometric series with a=7a = 7a=7 and r=14r = \frac{1}{4}r=41​.

    The series is:

    7,74,716,764,…7, \frac{7}{4}, \frac{7}{16}, \frac{7}{64}, \ldots7,47​,167​,647​,…

    Since ∣r∣=14<1|r| = \frac{1}{4} < 1∣r∣=41​<1, the series converges. Using the formula for the sum of an infinite geometric series:

    S∞=71−14=734=7×43=283≈9.33S_{\infty} = \frac{7}{1 - \frac{1}{4}} = \frac{7}{\frac{3}{4}} = \frac{7 \times 4}{3} = \frac{28}{3} \approx 9.33S∞​=1−41​7​=43​7​=37×4​=328​≈9.33

    So, the sum of the infinite geometric series is approximately 9.339.339.33.

    Summary:

    • A geometric series is the sum of the terms of a geometric sequence.

    • The sum of the first nnn terms of a finite geometric series is given by:

      Sn=a(1−rn)1−r,forr≠1S_n = \frac{a(1 - r^n)}{1 - r}, \quad \text{for} \quad r \neq 1Sn​=1−ra(1−rn)​,forr=1
    • The sum of an infinite geometric series is given by:

      S∞=a1−r,for∣r∣<1S_{\infty} = \frac{a}{1 - r}, \quad \text{for} \quad |r| < 1S∞​=1−ra​,for∣r∣<1
    • Convergence occurs when ∣r∣<1|r| < 1∣r∣<1, and divergence occurs when ∣r∣≥1|r| \geq 1∣r∣≥1.

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