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Study PortalMD-002Area As Limit Sigma No…
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    MD-002

    Math Deficiency – II

    Progress0 / 32 done
    Topics32
    1Complex Numbers2Arithmetic with Complex Numbers (Add, subtract, multiply and divide complex numbers)3Trigonometric Polar Form of Complex Numbers4De Moivre's Theorem and nth Roots5Recursion6Sequences and Series7Sigma Notation8Arithmetic Series9Geometric Series (Sum infinite and finite geometric series and categorize geometric series)10Counting with Permutations and Combinations11Basic Probability12Binomial Theorem
    13Notation, Graphs to Find Limits, Tables to Find Limits14Substitution to Find Limits, Rationalization to Find Limits15One Sided Limits and Continuity
    16Instantaneous Rate of Change17Tangent Lines and Rates of Change
    18The Derivative Function19Introduction to Techniques of Differentiation20The Product and Quotient Rules21Derivatives of Trigonometric Functions22The Chain Rule23Derivatives of Logarithmic Functions24Derivatives of Exponential and Inverse Trigonometric Functions25Increase, Decrease, and Concavity26Relative Extrema, Absolute Maxima and Minima
    27An Overview of the Area Problem28Area Under a Curve29The Indefinite Integral30Integration by Substitution31The Definition of Area as a Limit; Sigma Notation32The Definite Integral
    6 min read
    Topic 31 of 32
    Topic Study Note Illustration
    31

    The Definition of Area as a Limit; Sigma Notation

    The concept of area as a limit is the foundation of definite integrals. It is based on approximating the area under a curve using rectangles , and...

    The Definition of Area as a Limit & Sigma Notation

    The concept of area as a limit is the foundation of definite integrals. It is based on approximating the area under a curve using rectangles, and then refining the approximation by taking the limit as the number of rectangles approaches infinity. Sigma (Σ\SigmaΣ) notation is used to express these sums concisely.


    1. Approximating Area Using Rectangles (Riemann Sums)

    To approximate the area under a curve y=f(x)y = f(x)y=f(x) on the interval [a,b][a, b][a,b]:

    1. Divide the interval into nnn subintervals of equal width:

      Δx=b−an\Delta x = \frac{b-a}{n}Δx=nb−a​
    2. Choose sample points xi∗x_i^*xi∗​ in each subinterval.

    3. Form rectangles using f(xi∗)f(x_i^*)f(xi∗​) as the height.

    4. Compute the sum of the rectangle areas:

      An=∑i=1nf(xi∗)ΔxA_n = \sum_{i=1}^{n} f(x_i^*) \Delta xAn​=i=1∑n​f(xi∗​)Δx
    5. Take the limit as n→∞n \to \inftyn→∞ to get the exact area:

      A=lim⁡n→∞∑i=1nf(xi∗)ΔxA = \lim_{n \to \infty} \sum_{i=1}^{n} f(x_i^*) \Delta xA=n→∞lim​i=1∑n​f(xi∗​)Δx

    This limit defines the definite integral:

    A=∫abf(x) dxA = \int_{a}^{b} f(x) \, dxA=∫ab​f(x)dx

    2. Sigma Notation (Σ\SigmaΣ)

    Sigma notation is a shorthand way of writing sums. It is written as:

    ∑i=1nai\sum_{i=1}^{n} a_ii=1∑n​ai​

    where:

    • iii is the index of summation.
    • aia_iai​ is the term being summed.
    • nnn is the number of terms.

    For example:

    ∑i=14i=1+2+3+4=10\sum_{i=1}^{4} i = 1 + 2 + 3 + 4 = 10i=1∑4​i=1+2+3+4=10

    3. Riemann Sums in Sigma Notation

    Using sigma notation, the sum of areas of rectangles is:

    An=∑i=1nf(xi∗)ΔxA_n = \sum_{i=1}^{n} f(x_i^*) \Delta xAn​=i=1∑n​f(xi∗​)Δx
    • If xi∗x_i^*xi∗​ is the left endpoint, it's called a left Riemann sum.
    • If xi∗x_i^*xi∗​ is the right endpoint, it's called a right Riemann sum.
    • If xi∗x_i^*xi∗​ is the midpoint, it's called a midpoint Riemann sum.

    As n→∞n \to \inftyn→∞, the sum approaches the exact area under the curve.


    4. Example: Approximating an Integral Using Sigma Notation

    Find the approximate area under f(x)=x2f(x) = x^2f(x)=x2 on [0,2][0, 2][0,2] using 4 rectangles with right endpoints.

    Step 1: Find Δx\Delta xΔx

    Δx=b−an=2−04=0.5\Delta x = \frac{b-a}{n} = \frac{2-0}{4} = 0.5Δx=nb−a​=42−0​=0.5

    Step 2: Identify Right Endpoints

    Right endpoints:

    x1∗=0.5,x2∗=1,x3∗=1.5,x4∗=2x_1^* = 0.5, \quad x_2^* = 1, \quad x_3^* = 1.5, \quad x_4^* = 2x1∗​=0.5,x2∗​=1,x3∗​=1.5,x4∗​=2

    Step 3: Compute Function Values

    f(0.5)=(0.5)2=0.25,f(1)=1,f(1.5)=2.25,f(2)=4f(0.5) = (0.5)^2 = 0.25, \quad f(1) = 1, \quad f(1.5) = 2.25, \quad f(2) = 4f(0.5)=(0.5)2=0.25,f(1)=1,f(1.5)=2.25,f(2)=4

    Step 4: Compute Approximate Area

    A4=∑i=14f(xi∗)ΔxA_4 = \sum_{i=1}^{4} f(x_i^*) \Delta xA4​=i=1∑4​f(xi∗​)Δx =(0.25+1+2.25+4)×0.5= (0.25 + 1 + 2.25 + 4) \times 0.5=(0.25+1+2.25+4)×0.5 =3.75= 3.75=3.75

    Step 5: Exact Area Using Integration

    ∫02x2 dx=[x33]02=83≈2.67\int_{0}^{2} x^2 \, dx = \left[ \frac{x^3}{3} \right]_{0}^{2} = \frac{8}{3} \approx 2.67∫02​x2dx=[3x3​]02​=38​≈2.67

    As n→∞n \to \inftyn→∞, the Riemann sum approaches the integral's value.


    5. Importance of Area as a Limit

    • Foundation of Definite Integrals
    • Used in Physics (Work, displacement, fluid flow)
    • Economics (Revenue, cost functions)
    • Probability (Continuous probability distributions)

    Understanding area as a limit through Riemann sums builds the intuition for definite integration.

    ← Previous topic 30
    Integration by Substitution
    Next topic 32 →
    The Definite Integral

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