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    Math Deficiency – II
    MD-002
    Progress0 / 32 topics
    Topics
    1. Complex Numbers2. Arithmetic with Complex Numbers (Add, subtract, multiply and divide complex numbers)3. Trigonometric Polar Form of Complex Numbers4. De Moivre's Theorem and nth Roots5. Recursion6. Sequences and Series7. Sigma Notation8. Arithmetic Series9. Geometric Series (Sum infinite and finite geometric series and categorize geometric series)10. Counting with Permutations and Combinations11. Basic Probability12. Binomial Theorem13. Limit: Notation, Graphs to Find Limits, Tables to Find Limits14. Substitution to Find Limits, Rationalization to Find Limits15. One Sided Limits and Continuity16. Rate of Change: Instantaneous Rate of Change17. Tangent Lines and Rates of Change18. Derivatives: The Derivative Function19. Introduction to Techniques of Differentiation20. The Product and Quotient Rules21. Derivatives of Trigonometric Functions22. The Chain Rule23. Derivatives of Logarithmic Functions24. Derivatives of Exponential and Inverse Trigonometric Functions25. Increase, Decrease, and Concavity26. Relative Extrema, Absolute Maxima and Minima27. Integrals: An Overview of the Area Problem28. Area Under a Curve29. The Indefinite Integral30. Integration by Substitution31. The Definition of Area as a Limit; Sigma Notation32. The Definite Integral
    MD-002›The Chain Rule
    Math Deficiency – IITopic 22 of 32

    The Chain Rule

    11 minread
    1,819words
    Intermediatelevel

    The Chain Rule

    The Chain Rule is a fundamental technique in calculus that allows us to differentiate composite functions. A composite function is one in which one function is nested inside another. The Chain Rule helps us find the derivative of such functions by taking the derivative of the outer function and multiplying it by the derivative of the inner function.


    The Chain Rule Formula

    If you have a composite function f(x)=g(h(x))f(x) = g(h(x))f(x)=g(h(x)), where ggg is a function of h(x)h(x)h(x), and h(x)h(x)h(x) is a function of xxx, the Chain Rule states that the derivative of f(x)f(x)f(x) is:

    f′(x)=g′(h(x))⋅h′(x)f'(x) = g'(h(x)) \cdot h'(x)f′(x)=g′(h(x))⋅h′(x)

    This means you:

    1. Differentiate the outer function ggg with respect to its argument h(x)h(x)h(x).
    2. Multiply by the derivative of the inner function h(x)h(x)h(x).

    Steps to Apply the Chain Rule:

    1. Identify the outer function g(x)g(x)g(x) and the inner function h(x)h(x)h(x).
    2. Differentiate the outer function g(x)g(x)g(x) with respect to h(x)h(x)h(x), leaving the inner function h(x)h(x)h(x) unchanged.
    3. Multiply this derivative by the derivative of the inner function h(x)h(x)h(x).

    Example 1: Differentiating a Simple Composite Function

    Let’s differentiate f(x)=sin⁡(x2)f(x) = \sin(x^2)f(x)=sin(x2).

    1. Identify the outer and inner functions:

      • Outer function g(u)=sin⁡(u)g(u) = \sin(u)g(u)=sin(u), where u=x2u = x^2u=x2.
      • Inner function h(x)=x2h(x) = x^2h(x)=x2.
    2. Differentiate the outer function with respect to uuu:

      ddu(sin⁡(u))=cos⁡(u)\frac{d}{du}(\sin(u)) = \cos(u)dud​(sin(u))=cos(u)
    3. Differentiate the inner function with respect to xxx:

      ddx(x2)=2x\frac{d}{dx}(x^2) = 2xdxd​(x2)=2x
    4. Apply the Chain Rule:

      f′(x)=cos⁡(x2)⋅2xf'(x) = \cos(x^2) \cdot 2xf′(x)=cos(x2)⋅2x

    So, the derivative of f(x)=sin⁡(x2)f(x) = \sin(x^2)f(x)=sin(x2) is:

    f′(x)=2xcos⁡(x2)f'(x) = 2x \cos(x^2)f′(x)=2xcos(x2)

    Example 2: Differentiating a More Complex Function

    Let’s differentiate f(x)=ln⁡(3x2+5)f(x) = \ln(3x^2 + 5)f(x)=ln(3x2+5).

    1. Identify the outer and inner functions:

      • Outer function g(u)=ln⁡(u)g(u) = \ln(u)g(u)=ln(u), where u=3x2+5u = 3x^2 + 5u=3x2+5.
      • Inner function h(x)=3x2+5h(x) = 3x^2 + 5h(x)=3x2+5.
    2. Differentiate the outer function with respect to uuu:

      ddu(ln⁡(u))=1u\frac{d}{du}(\ln(u)) = \frac{1}{u}dud​(ln(u))=u1​
    3. Differentiate the inner function with respect to xxx:

      ddx(3x2+5)=6x\frac{d}{dx}(3x^2 + 5) = 6xdxd​(3x2+5)=6x
    4. Apply the Chain Rule:

      f′(x)=13x2+5⋅6xf'(x) = \frac{1}{3x^2 + 5} \cdot 6xf′(x)=3x2+51​⋅6x

    So, the derivative of f(x)=ln⁡(3x2+5)f(x) = \ln(3x^2 + 5)f(x)=ln(3x2+5) is:

    f′(x)=6x3x2+5f'(x) = \frac{6x}{3x^2 + 5}f′(x)=3x2+56x​

    Example 3: Chain Rule with Trigonometric Functions

    Let’s differentiate f(x)=sin⁡(5x3)f(x) = \sin(5x^3)f(x)=sin(5x3).

    1. Identify the outer and inner functions:

      • Outer function g(u)=sin⁡(u)g(u) = \sin(u)g(u)=sin(u), where u=5x3u = 5x^3u=5x3.
      • Inner function h(x)=5x3h(x) = 5x^3h(x)=5x3.
    2. Differentiate the outer function with respect to uuu:

      ddu(sin⁡(u))=cos⁡(u)\frac{d}{du}(\sin(u)) = \cos(u)dud​(sin(u))=cos(u)
    3. Differentiate the inner function with respect to xxx:

      ddx(5x3)=15x2\frac{d}{dx}(5x^3) = 15x^2dxd​(5x3)=15x2
    4. Apply the Chain Rule:

      f′(x)=cos⁡(5x3)⋅15x2f'(x) = \cos(5x^3) \cdot 15x^2f′(x)=cos(5x3)⋅15x2

    So, the derivative of f(x)=sin⁡(5x3)f(x) = \sin(5x^3)f(x)=sin(5x3) is:

    f′(x)=15x2cos⁡(5x3)f'(x) = 15x^2 \cos(5x^3)f′(x)=15x2cos(5x3)

    Example 4: Chain Rule with Exponential Functions

    Let’s differentiate f(x)=e3x2+2xf(x) = e^{3x^2 + 2x}f(x)=e3x2+2x.

    1. Identify the outer and inner functions:

      • Outer function g(u)=eug(u) = e^ug(u)=eu, where u=3x2+2xu = 3x^2 + 2xu=3x2+2x.
      • Inner function h(x)=3x2+2xh(x) = 3x^2 + 2xh(x)=3x2+2x.
    2. Differentiate the outer function with respect to uuu:

      ddu(eu)=eu\frac{d}{du}(e^u) = e^udud​(eu)=eu
    3. Differentiate the inner function with respect to xxx:

      ddx(3x2+2x)=6x+2\frac{d}{dx}(3x^2 + 2x) = 6x + 2dxd​(3x2+2x)=6x+2
    4. Apply the Chain Rule:

      f′(x)=e3x2+2x⋅(6x+2)f'(x) = e^{3x^2 + 2x} \cdot (6x + 2)f′(x)=e3x2+2x⋅(6x+2)

    So, the derivative of f(x)=e3x2+2xf(x) = e^{3x^2 + 2x}f(x)=e3x2+2x is:

    f′(x)=(6x+2)e3x2+2xf'(x) = (6x + 2)e^{3x^2 + 2x}f′(x)=(6x+2)e3x2+2x

    Key Points to Remember

    • The Chain Rule is used when differentiating a composite function, which is a function inside another function.
    • The Chain Rule formula is: f′(x)=g′(h(x))⋅h′(x)f'(x) = g'(h(x)) \cdot h'(x)f′(x)=g′(h(x))⋅h′(x), where g(h(x))g(h(x))g(h(x)) is the composite function.
    • Step-by-step approach:
      1. Differentiate the outer function with respect to the inner function.
      2. Multiply by the derivative of the inner function.
    • Be mindful of nested functions, including polynomials, trigonometric functions, logarithms, and exponentials.

    Summary of the Chain Rule:

    1. Composite Function: f(x)=g(h(x))f(x) = g(h(x))f(x)=g(h(x))
    2. Derivative: f′(x)=g′(h(x))⋅h′(x)f'(x) = g'(h(x)) \cdot h'(x)f′(x)=g′(h(x))⋅h′(x)
    3. Steps:
      • Differentiate the outer function.
      • Multiply by the derivative of the inner function.
    4. Application: The Chain Rule applies to a wide range of composite functions (including polynomials, trigonometric, logarithmic, and exponential functions).

    By mastering the Chain Rule, you can differentiate complex functions that involve multiple layers of composition and relationships between functions.

    Previous topic 21
    Derivatives of Trigonometric Functions
    Next topic 23
    Derivatives of Logarithmic Functions

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