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    Math Deficiency – II
    MD-002
    Progress0 / 32 topics
    Topics
    1. Complex Numbers2. Arithmetic with Complex Numbers (Add, subtract, multiply and divide complex numbers)3. Trigonometric Polar Form of Complex Numbers4. De Moivre's Theorem and nth Roots5. Recursion6. Sequences and Series7. Sigma Notation8. Arithmetic Series9. Geometric Series (Sum infinite and finite geometric series and categorize geometric series)10. Counting with Permutations and Combinations11. Basic Probability12. Binomial Theorem13. Limit: Notation, Graphs to Find Limits, Tables to Find Limits14. Substitution to Find Limits, Rationalization to Find Limits15. One Sided Limits and Continuity16. Rate of Change: Instantaneous Rate of Change17. Tangent Lines and Rates of Change18. Derivatives: The Derivative Function19. Introduction to Techniques of Differentiation20. The Product and Quotient Rules21. Derivatives of Trigonometric Functions22. The Chain Rule23. Derivatives of Logarithmic Functions24. Derivatives of Exponential and Inverse Trigonometric Functions25. Increase, Decrease, and Concavity26. Relative Extrema, Absolute Maxima and Minima27. Integrals: An Overview of the Area Problem28. Area Under a Curve29. The Indefinite Integral30. Integration by Substitution31. The Definition of Area as a Limit; Sigma Notation32. The Definite Integral
    MD-002›De Moivre's Theorem and nth Roots
    Math Deficiency – IITopic 4 of 32

    De Moivre's Theorem and nth Roots

    7 minread
    1,224words
    Intermediatelevel

    De Moivre's Theorem and nth Roots of Complex Numbers

    1. De Moivre's Theorem

    Statement:
    For any complex number in polar form z=r(cos⁡θ+isin⁡θ)z = r (\cos \theta + i \sin \theta)z=r(cosθ+isinθ) and any integer nnn,
    zn=rn(cos⁡(nθ)+isin⁡(nθ)).z^n = r^n \left( \cos(n\theta) + i \sin(n\theta) \right).zn=rn(cos(nθ)+isin(nθ)).

    Proof:

    • For positive integers, use mathematical induction:
      • Base case (n=1n = 1n=1): Trivially true.
      • Inductive step: Assume true for n=kn = kn=k, then show for n=k+1n = k+1n=k+1 using angle addition formulas.
    • For negative integers, use z−n=1znz^{-n} = \frac{1}{z^n}z−n=zn1​ and trigonometric identities.

    Applications:

    • Efficiently compute powers of complex numbers.
    • Derive multiple-angle trigonometric identities (e.g., cos⁡(3θ)\cos(3\theta)cos(3θ)).

    2. Finding nth Roots of a Complex Number

    Given z=r(cos⁡θ+isin⁡θ)z = r (\cos \theta + i \sin \theta)z=r(cosθ+isinθ), its nnn-th roots are:
    zn=r1/n[cos⁡(θ+2kπn)+isin⁡(θ+2kπn)],\sqrt[n]{z} = r^{1/n} \left[ \cos\left( \frac{\theta + 2k\pi}{n} \right) + i \sin\left( \frac{\theta + 2k\pi}{n} \right) \right],nz​=r1/n[cos(nθ+2kπ​)+isin(nθ+2kπ​)],
    where k=0,1,2,…,n−1k = 0, 1, 2, \dots, n-1k=0,1,2,…,n−1.

    Key Properties:

    • Number of roots: Exactly nnn distinct roots (due to periodicity of 2π2\pi2π).
    • Geometric interpretation: Roots lie on a circle of radius r1/nr^{1/n}r1/n in the complex plane, spaced at angles of 2πn\frac{2\pi}{n}n2π​.

    Example (Cube Roots of Unity):
    Solve z3=1z^3 = 1z3=1:

    • Polar form: 1=1(cos⁡0+isin⁡0)1 = 1 (\cos 0 + i \sin 0)1=1(cos0+isin0).
    • Roots:
      ωk=cos⁡(2kπ3)+isin⁡(2kπ3),k=0,1,2.\omega_k = \cos\left( \frac{2k\pi}{3} \right) + i \sin\left( \frac{2k\pi}{3} \right), \quad k = 0, 1, 2.ωk​=cos(32kπ​)+isin(32kπ​),k=0,1,2.
      Explicitly:
      • ω0=1\omega_0 = 1ω0​=1,
      • ω1=−12+i32\omega_1 = -\frac{1}{2} + i \frac{\sqrt{3}}{2}ω1​=−21​+i23​​,
      • ω2=−12−i32\omega_2 = -\frac{1}{2} - i \frac{\sqrt{3}}{2}ω2​=−21​−i23​​.

    3. Connection to Polynomial Equations

    • The equation zn=wz^n = wzn=w has nnn solutions (roots) in the complex plane.
    • Fundamental Theorem of Algebra: Every non-constant polynomial of degree nnn has exactly nnn roots in C\mathbb{C}C.

    4. Practical Computations

    1. Step 1: Convert the complex number to polar form z=r(cos⁡θ+isin⁡θ)z = r (\cos \theta + i \sin \theta)z=r(cosθ+isinθ).
    2. Step 2: Apply De Moivre’s formula for roots.
    3. Step 3: Evaluate for k=0k = 0k=0 to k=n−1k = n-1k=n−1 to list all roots.

    Example: Find all 4th roots of z=16(cos⁡π+isin⁡π)z = 16 (\cos \pi + i \sin \pi)z=16(cosπ+isinπ).

    • Roots:
      2[cos⁡(π+2kπ4)+isin⁡(π+2kπ4)],k=0,1,2,3.2 \left[ \cos\left( \frac{\pi + 2k\pi}{4} \right) + i \sin\left( \frac{\pi + 2k\pi}{4} \right) \right], \quad k = 0, 1, 2, 3.2[cos(4π+2kπ​)+isin(4π+2kπ​)],k=0,1,2,3.
    • Explicit solutions:
      • k=0k=0k=0: 2(cos⁡π4+isin⁡π4)=2+i22 \left( \cos \frac{\pi}{4} + i \sin \frac{\pi}{4} \right) = \sqrt{2} + i \sqrt{2}2(cos4π​+isin4π​)=2​+i2​,
      • k=1k=1k=1: 2(cos⁡3π4+isin⁡3π4)=−2+i22 \left( \cos \frac{3\pi}{4} + i \sin \frac{3\pi}{4} \right) = -\sqrt{2} + i \sqrt{2}2(cos43π​+isin43π​)=−2​+i2​,
      • k=2k=2k=2: 2(cos⁡5π4+isin⁡5π4)=−2−i22 \left( \cos \frac{5\pi}{4} + i \sin \frac{5\pi}{4} \right) = -\sqrt{2} - i \sqrt{2}2(cos45π​+isin45π​)=−2​−i2​,
      • k=3k=3k=3: 2(cos⁡7π4+isin⁡7π4)=2−i22 \left( \cos \frac{7\pi}{4} + i \sin \frac{7\pi}{4} \right) = \sqrt{2} - i \sqrt{2}2(cos47π​+isin47π​)=2​−i2​.

    5. Applications

    • Engineering: Solving AC circuit problems with phasors.
    • Computer Graphics: Rotations and scaling using complex multiplication.
    • Quantum Physics: Wavefunction symmetries and eigenvalue problems.

    De Moivre’s Theorem and nth roots unify algebraic and geometric perspectives of complex numbers, enabling elegant solutions to polynomial equations and periodic systems.

    Previous topic 3
    Trigonometric Polar Form of Complex Numbers
    Next topic 5
    Recursion

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