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    Discrete Structures
    GE-167
    Progress0 / 67 topics
    Topics
    1. Mathematical Reasoning: Propositional and Predicate Logic2. Propositional Logic: Logical Operators3. Translations Between Symbolic Expressions and Formal English Expression4. Logical Equivalences5. Predicate Logic: Quantifiers6. Nested Quantification7. Equivalences in Predicate Logic8. Translations Between Symbolic Forms and Formal English9. Rules of Inference: Proof Methods and Strategies10. Direct Proof11. Proof by Contraposition12. Proof by Induction13. Proof by Implication14. Existence Proof15. Uniqueness Proofs16. Trivial Proofs17. Vacuous Proofs18. Sets: Notations and Set Operations19. Venn Diagrams20. Countable and Uncountable Sets21. Relations: Equivalence Relations and Partitions22. Partial Orderings23. Recurrence Relations24. Functions: Injective, Surjective, Bijective25. Special Types of Functions26. Function Composition27. Inverse Functions28. Recursive Functions29. Compositions30. Number Theory: Sequences and Series31. Counting: Inclusion and Exclusion Principle32. Pigeonhole Principle33. Permutations and Combinations34. Integers and Divisibility: Division Theorem35. Modular Arithmetic36. LCM and GCD37. Euclidean and Extended Euclidean Method38. Finding Solutions to Congruence39. Primes: Fundamental Theorem of Arithmetic40. Characterizations of Primes41. Mersenne Primes42. Induction: Weak Induction43. Strong Induction44. Recursion and Recurrences: Formulation of Recurrences45. Closed Formulas46. Counting: Product Rule and Sum Rule47. Principle of Inclusion-Exclusion48. Binomial Coefficients49. Pascal's Identity and Pascal’s Triangle50. Binomial Theorem51. Relations: Reflexive, Symmetric, Transitive, and Antisymmetric52. Equivalence Relations and Equivalence Classes53. Partial Orders54. Graph Theory: Terminologies55. Elements of Graph Theory56. Planar Graphs57. Graph Coloring58. Euler Graph59. Hamiltonian Path60. Rooted Trees61. Graph Traversals62. Handshaking Lemma and Corollary63. Special Families of Graphs64. Graph Isomorphism65. Planarity in Graphs66. Eulerian and Hamiltonian Graphs67. Trees in Graph Theory
    GE-167›Proof by Implication
    Discrete StructuresTopic 13 of 67

    Proof by Implication

    6 minread
    1,079words
    Intermediatelevel

    Proof by Implication

    Proof by Implication (or Direct Proof of Implication) is a method used to prove a logical implication of the form:

    P  ⟹  QP \implies QP⟹Q

    where PPP and QQQ are statements, and the goal is to prove that if PPP is true, then QQQ must also be true.

    The structure of the implication P  ⟹  QP \implies QP⟹Q is:

    • PPP is called the hypothesis or antecedent.
    • QQQ is called the conclusion or consequent.

    Steps in a Proof by Implication

    1. Assume the Hypothesis is True:

      • Start by assuming that the hypothesis PPP is true. This is the foundation of a proof by implication because we are trying to show that if PPP holds, then QQQ must follow.
    2. Derive the Conclusion:

      • From the assumption that PPP is true, you logically deduce that QQQ must also be true. This is done through valid logical steps, such as using known theorems, definitions, or rules of inference.
    3. Conclude the Proof:

      • Once you've established that QQQ follows from the assumption of PPP, you can conclude that the implication P  ⟹  QP \implies QP⟹Q is true.

    Example of Proof by Implication

    Example 1: Prove that if nnn is an even integer, then n2n^2n2 is even.

    We need to prove that if nnn is even, n2n^2n2 is also even. The implication we are trying to prove is:

    If n is even, then n2 is even.\text{If } n \text{ is even, then } n^2 \text{ is even.}If n is even, then n2 is even.

    Step 1: Assume the Hypothesis is True

    • Assume nnn is even. By the definition of an even integer, this means that there exists an integer kkk such that:
    n=2kn = 2kn=2k

    Step 2: Derive the Conclusion

    • We need to prove that n2n^2n2 is even. Starting with the assumption n=2kn = 2kn=2k, we calculate n2n^2n2:
    n2=(2k)2=4k2n^2 = (2k)^2 = 4k^2n2=(2k)2=4k2
    • Notice that 4k24k^24k2 is clearly divisible by 2 (since 4k2=2⋅(2k2)4k^2 = 2 \cdot (2k^2)4k2=2⋅(2k2), and it is of the form 2m2m2m, where mmm is an integer). Therefore, n2n^2n2 is even.

    Step 3: Conclusion

    • Since we have shown that n2n^2n2 is even when nnn is even, we conclude that if nnn is even, then n2n^2n2 is even.

    Thus, the implication P  ⟹  QP \implies QP⟹Q is proven: If nnn is even, then n2n^2n2 is even.


    Example 2: Prove that if a number nnn is divisible by 4, then nnn is divisible by 2.

    We need to prove the following implication:

    If n is divisible by 4, then n is divisible by 2.\text{If } n \text{ is divisible by 4, then } n \text{ is divisible by 2.}If n is divisible by 4, then n is divisible by 2.

    Step 1: Assume the Hypothesis is True

    • Assume that nnn is divisible by 4. By the definition of divisibility, there exists an integer kkk such that:
    n=4kn = 4kn=4k

    Step 2: Derive the Conclusion

    • We need to prove that nnn is divisible by 2. Since n=4kn = 4kn=4k, we can rewrite nnn as:
    n=2(2k)n = 2(2k)n=2(2k)
    • This shows that nnn is of the form 2m2m2m, where m=2km = 2km=2k is an integer. Therefore, nnn is divisible by 2.

    Step 3: Conclusion

    • Since we have shown that nnn is divisible by 2 when nnn is divisible by 4, we conclude that if nnn is divisible by 4, then nnn is divisible by 2.

    Thus, the implication P  ⟹  QP \implies QP⟹Q is proven: If nnn is divisible by 4, then nnn is divisible by 2.


    Key Points to Remember in Proof by Implication

    1. Start with the assumption that the hypothesis is true: This is essential because in a proof of implication, you prove the conclusion by assuming that the hypothesis holds.

    2. Focus on deriving the conclusion: Use logical reasoning and known facts to show that the conclusion necessarily follows from the assumption.

    3. The structure of an implication: The structure of an implication is P  ⟹  QP \implies QP⟹Q, and you must prove that if PPP is true, then QQQ must also be true. If you successfully show this, the implication is true.

    4. No need to prove the converse: In a proof by implication, you are only proving that P  ⟹  QP \implies QP⟹Q holds; you do not need to prove the converse (that Q  ⟹  PQ \implies PQ⟹P) unless asked.


    Conclusion

    Proof by implication is a powerful technique used to establish the truth of statements of the form "If PPP, then QQQ." The proof involves assuming that PPP is true and showing that this assumption leads logically to QQQ. By proving this, you have proven the truth of the implication P  ⟹  QP \implies QP⟹Q. This method is commonly used in mathematics and logic when dealing with conditional statements.

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    Proof by Induction
    Next topic 14
    Existence Proof

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