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Study PortalGE-167Pascals Identity Pasca…
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    GE-167

    Discrete Structures

    Progress0 / 67 done
    Topics67
    1Propositional and Predicate Logic
    2Logical Operators3Translations Between Symbolic Expressions and Formal English Expression4Logical Equivalences
    5Quantifiers6Nested Quantification7Equivalences in Predicate Logic8Translations Between Symbolic Forms and Formal English
    9Proof Methods and Strategies10Direct Proof11Proof by Contraposition12Proof by Induction13Proof by Implication14Existence Proof15Uniqueness Proofs16Trivial Proofs17Vacuous Proofs
    18Notations and Set Operations19Venn Diagrams20Countable and Uncountable Sets
    21Equivalence Relations and Partitions22Partial Orderings23Recurrence Relations51Reflexive, Symmetric, Transitive, and Antisymmetric52Equivalence Relations and Equivalence Classes53Partial Orders
    24Injective, Surjective, Bijective25Special Types of Functions26Function Composition27Inverse Functions28Recursive Functions29Compositions
    30Sequences and Series
    31Inclusion and Exclusion Principle32Pigeonhole Principle33Permutations and Combinations46Product Rule and Sum Rule47Principle of Inclusion-Exclusion48Binomial Coefficients49Pascal's Identity and Pascal’s Triangle50Binomial Theorem
    34Division Theorem35Modular Arithmetic36LCM and GCD37Euclidean and Extended Euclidean Method38Finding Solutions to Congruence
    39Fundamental Theorem of Arithmetic40Characterizations of Primes41Mersenne Primes
    42Weak Induction43Strong Induction
    44Formulation of Recurrences45Closed Formulas
    54Terminologies55Elements of Graph Theory56Planar Graphs57Graph Coloring58Euler Graph59Hamiltonian Path60Rooted Trees61Graph Traversals62Handshaking Lemma and Corollary63Special Families of Graphs64Graph Isomorphism65Planarity in Graphs66Eulerian and Hamiltonian Graphs67Trees in Graph Theory
    8 min read
    Topic 49 of 67
    Topic Study Note Illustration
    49

    Pascal's Identity and Pascal’s Triangle

    Pascal's Identity is a combinatorial identity that relates binomial coefficients and plays a significant role in combinatorics and algebra. Pascal's Triangle is a geometric arrangement of binomial...

    Pascal's Identity and Pascal’s Triangle

    Pascal's Identity is a combinatorial identity that relates binomial coefficients and plays a significant role in combinatorics and algebra. Pascal's Triangle is a geometric arrangement of binomial coefficients, and Pascal's Identity provides a recursive relationship that can generate the coefficients in the triangle.

    Pascal's Identity

    Pascal's Identity states the following:

    (nk)=(n−1k−1)+(n−1k)\binom{n}{k} = \binom{n-1}{k-1} + \binom{n-1}{k}(kn​)=(k−1n−1​)+(kn−1​)

    This identity expresses the value of a binomial coefficient (nk)\binom{n}{k}(kn​) as the sum of two other binomial coefficients:

    1. (n−1k−1)\binom{n-1}{k-1}(k−1n−1​), which represents the number of ways to choose k−1k-1k−1 elements from n−1n-1n−1 elements.
    2. (n−1k)\binom{n-1}{k}(kn−1​), which represents the number of ways to choose kkk elements from n−1n-1n−1 elements.

    Interpretation of Pascal's Identity

    Pascal's Identity can be understood in terms of a combinatorial argument. Consider a set of nnn elements and you want to choose kkk elements from that set. You can divide this problem into two cases:

    • Case 1: The first element is included in the selection. If you include the first element, you need to choose k−1k-1k−1 elements from the remaining n−1n-1n−1 elements, which can be done in (n−1k−1)\binom{n-1}{k-1}(k−1n−1​) ways.

    • Case 2: The first element is not included in the selection. In this case, you need to choose all kkk elements from the remaining n−1n-1n−1 elements, which can be done in (n−1k)\binom{n-1}{k}(kn−1​) ways.

    By combining these two cases, the total number of ways to choose kkk elements from nnn elements is the sum of the two cases:

    (nk)=(n−1k−1)+(n−1k)\binom{n}{k} = \binom{n-1}{k-1} + \binom{n-1}{k}(kn​)=(k−1n−1​)+(kn−1​)

    This is the essence of Pascal's Identity.

    Pascal’s Triangle

    Pascal's Triangle is a triangular arrangement of numbers in which each number is the sum of the two numbers directly above it. The numbers in Pascal’s Triangle correspond to the binomial coefficients.

    Construction of Pascal’s Triangle

    To construct Pascal’s Triangle:

    1. Start with a 1 at the top, which corresponds to (00)\binom{0}{0}(00​).
    2. Each number in the triangle is the sum of the two numbers directly above it.
    3. The first and last number in each row is always 1, corresponding to (n0)\binom{n}{0}(0n​) and (nn)\binom{n}{n}(nn​), respectively.

    Here are the first few rows of Pascal’s Triangle:

    111121133114641151010511615201561\begin{matrix} 1 \\ 1 & 1 \\ 1 & 2 & 1 \\ 1 & 3 & 3 & 1 \\ 1 & 4 & 6 & 4 & 1 \\ 1 & 5 & 10 & 10 & 5 & 1 \\ 1 & 6 & 15 & 20 & 15 & 6 & 1 \\ \end{matrix}1111111​123456​1361015​141020​1515​16​1​

    The Structure of Pascal’s Triangle

    • Row n contains the binomial coefficients for the expansion of (x+y)n(x + y)^n(x+y)n. For example, the 3rd row 1,3,3,11, 3, 3, 11,3,3,1 corresponds to the coefficients of (x+y)3(x + y)^3(x+y)3, which is expanded as:
    (x+y)3=x3+3x2y+3xy2+y3(x + y)^3 = x^3 + 3x^2y + 3xy^2 + y^3(x+y)3=x3+3x2y+3xy2+y3
    • The kkk-th number in row nnn is (nk)\binom{n}{k}(kn​), which is the binomial coefficient corresponding to the number of ways to choose kkk elements from nnn elements.

    Using Pascal’s Triangle

    Pascal’s Triangle is a quick way to find binomial coefficients for small values of nnn and kkk. For example:

    • To find (52)\binom{5}{2}(25​), look in the 5th row (counting from 0) and the 2nd position (counting from 0). The value is 101010.

    • To find (41)\binom{4}{1}(14​), look in the 4th row and the 1st position. The value is 444.

    Relationship Between Pascal’s Identity and Pascal’s Triangle

    Pascal’s Identity explains the recursive structure of Pascal's Triangle. Each entry in the triangle is generated by adding the two entries directly above it. This matches the recurrence relation given by Pascal's Identity:

    (nk)=(n−1k−1)+(n−1k)\binom{n}{k} = \binom{n-1}{k-1} + \binom{n-1}{k}(kn​)=(k−1n−1​)+(kn−1​)

    For example, consider the 4th row of Pascal’s Triangle: 1,3,3,11, 3, 3, 11,3,3,1. To verify Pascal’s Identity:

    • (31)=(20)+(21)=1+2=3\binom{3}{1} = \binom{2}{0} + \binom{2}{1} = 1 + 2 = 3(13​)=(02​)+(12​)=1+2=3,
    • (32)=(21)+(22)=2+1=3\binom{3}{2} = \binom{2}{1} + \binom{2}{2} = 2 + 1 = 3(23​)=(12​)+(22​)=2+1=3.

    This is consistent with the numbers in the 4th row of Pascal’s Triangle.

    Applications of Pascal’s Identity and Pascal’s Triangle

    1. Binomial Expansions: Pascal’s Triangle gives the coefficients for the expansion of binomials raised to any power. For example, the coefficients in the expansion of (x+y)5(x + y)^5(x+y)5 are found in the 5th row of Pascal's Triangle: 1,5,10,10,5,11, 5, 10, 10, 5, 11,5,10,10,5,1.

    2. Combinatorics: Pascal’s Identity and Pascal’s Triangle are widely used in counting problems, where you need to find how many ways there are to choose kkk items from a set of nnn items.

    3. Probability Theory: Binomial coefficients (and Pascal’s Triangle) are used in calculating probabilities in situations involving repeated trials (e.g., the binomial distribution).

    4. Recursive Algorithms: Pascal’s Identity is used in recursive algorithms to calculate binomial coefficients and in dynamic programming approaches to optimize such calculations.

    Conclusion

    Pascal’s Identity provides a recursive relationship for binomial coefficients, while Pascal’s Triangle is a convenient way to visualize and calculate those coefficients. Together, they form an essential tool for solving problems in combinatorics, algebra, and probability. Pascal’s Triangle allows you to quickly reference binomial coefficients, and Pascal’s Identity gives a deeper understanding of the relationships between those coefficients.

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    Binomial Coefficients
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    Binomial Theorem

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