ScholarQuill logoScholarQuillUniversity Notes
  • Notes
  • Past Papers
  • Blogs
  • Todo
Login
ScholarQuill logoScholarQuillUniversity Notes
Login
NotesPast PapersBlogsTodo
More
SubjectsDiscussionCGPA CalculatorGPA CalculatorStudent PortalCourse Outline
About
About usPrivacy PolicyReportContact
Notes
Past Papers
Blogs
Todo
Analytics
    Current Subject
    🧩
    Discrete Structures
    GE-167
    Progress0 / 67 topics
    Topics
    1. Mathematical Reasoning: Propositional and Predicate Logic2. Propositional Logic: Logical Operators3. Translations Between Symbolic Expressions and Formal English Expression4. Logical Equivalences5. Predicate Logic: Quantifiers6. Nested Quantification7. Equivalences in Predicate Logic8. Translations Between Symbolic Forms and Formal English9. Rules of Inference: Proof Methods and Strategies10. Direct Proof11. Proof by Contraposition12. Proof by Induction13. Proof by Implication14. Existence Proof15. Uniqueness Proofs16. Trivial Proofs17. Vacuous Proofs18. Sets: Notations and Set Operations19. Venn Diagrams20. Countable and Uncountable Sets21. Relations: Equivalence Relations and Partitions22. Partial Orderings23. Recurrence Relations24. Functions: Injective, Surjective, Bijective25. Special Types of Functions26. Function Composition27. Inverse Functions28. Recursive Functions29. Compositions30. Number Theory: Sequences and Series31. Counting: Inclusion and Exclusion Principle32. Pigeonhole Principle33. Permutations and Combinations34. Integers and Divisibility: Division Theorem35. Modular Arithmetic36. LCM and GCD37. Euclidean and Extended Euclidean Method38. Finding Solutions to Congruence39. Primes: Fundamental Theorem of Arithmetic40. Characterizations of Primes41. Mersenne Primes42. Induction: Weak Induction43. Strong Induction44. Recursion and Recurrences: Formulation of Recurrences45. Closed Formulas46. Counting: Product Rule and Sum Rule47. Principle of Inclusion-Exclusion48. Binomial Coefficients49. Pascal's Identity and Pascal’s Triangle50. Binomial Theorem51. Relations: Reflexive, Symmetric, Transitive, and Antisymmetric52. Equivalence Relations and Equivalence Classes53. Partial Orders54. Graph Theory: Terminologies55. Elements of Graph Theory56. Planar Graphs57. Graph Coloring58. Euler Graph59. Hamiltonian Path60. Rooted Trees61. Graph Traversals62. Handshaking Lemma and Corollary63. Special Families of Graphs64. Graph Isomorphism65. Planarity in Graphs66. Eulerian and Hamiltonian Graphs67. Trees in Graph Theory
    GE-167›Pascal's Identity and Pascal’s Triangle
    Discrete StructuresTopic 49 of 67

    Pascal's Identity and Pascal’s Triangle

    8 minread
    1,438words
    Intermediatelevel

    Pascal's Identity and Pascal’s Triangle

    Pascal's Identity is a combinatorial identity that relates binomial coefficients and plays a significant role in combinatorics and algebra. Pascal's Triangle is a geometric arrangement of binomial coefficients, and Pascal's Identity provides a recursive relationship that can generate the coefficients in the triangle.

    Pascal's Identity

    Pascal's Identity states the following:

    (nk)=(n−1k−1)+(n−1k)\binom{n}{k} = \binom{n-1}{k-1} + \binom{n-1}{k}(kn​)=(k−1n−1​)+(kn−1​)

    This identity expresses the value of a binomial coefficient (nk)\binom{n}{k}(kn​) as the sum of two other binomial coefficients:

    1. (n−1k−1)\binom{n-1}{k-1}(k−1n−1​), which represents the number of ways to choose k−1k-1k−1 elements from n−1n-1n−1 elements.
    2. (n−1k)\binom{n-1}{k}(kn−1​), which represents the number of ways to choose kkk elements from n−1n-1n−1 elements.

    Interpretation of Pascal's Identity

    Pascal's Identity can be understood in terms of a combinatorial argument. Consider a set of nnn elements and you want to choose kkk elements from that set. You can divide this problem into two cases:

    • Case 1: The first element is included in the selection. If you include the first element, you need to choose k−1k-1k−1 elements from the remaining n−1n-1n−1 elements, which can be done in (n−1k−1)\binom{n-1}{k-1}(k−1n−1​) ways.

    • Case 2: The first element is not included in the selection. In this case, you need to choose all kkk elements from the remaining n−1n-1n−1 elements, which can be done in (n−1k)\binom{n-1}{k}(kn−1​) ways.

    By combining these two cases, the total number of ways to choose kkk elements from nnn elements is the sum of the two cases:

    (nk)=(n−1k−1)+(n−1k)\binom{n}{k} = \binom{n-1}{k-1} + \binom{n-1}{k}(kn​)=(k−1n−1​)+(kn−1​)

    This is the essence of Pascal's Identity.

    Pascal’s Triangle

    Pascal's Triangle is a triangular arrangement of numbers in which each number is the sum of the two numbers directly above it. The numbers in Pascal’s Triangle correspond to the binomial coefficients.

    Construction of Pascal’s Triangle

    To construct Pascal’s Triangle:

    1. Start with a 1 at the top, which corresponds to (00)\binom{0}{0}(00​).
    2. Each number in the triangle is the sum of the two numbers directly above it.
    3. The first and last number in each row is always 1, corresponding to (n0)\binom{n}{0}(0n​) and (nn)\binom{n}{n}(nn​), respectively.

    Here are the first few rows of Pascal’s Triangle:

    111121133114641151010511615201561\begin{matrix} 1 \\ 1 & 1 \\ 1 & 2 & 1 \\ 1 & 3 & 3 & 1 \\ 1 & 4 & 6 & 4 & 1 \\ 1 & 5 & 10 & 10 & 5 & 1 \\ 1 & 6 & 15 & 20 & 15 & 6 & 1 \\ \end{matrix}1111111​123456​1361015​141020​1515​16​1​

    The Structure of Pascal’s Triangle

    • Row n contains the binomial coefficients for the expansion of (x+y)n(x + y)^n(x+y)n. For example, the 3rd row 1,3,3,11, 3, 3, 11,3,3,1 corresponds to the coefficients of (x+y)3(x + y)^3(x+y)3, which is expanded as:
    (x+y)3=x3+3x2y+3xy2+y3(x + y)^3 = x^3 + 3x^2y + 3xy^2 + y^3(x+y)3=x3+3x2y+3xy2+y3
    • The kkk-th number in row nnn is (nk)\binom{n}{k}(kn​), which is the binomial coefficient corresponding to the number of ways to choose kkk elements from nnn elements.

    Using Pascal’s Triangle

    Pascal’s Triangle is a quick way to find binomial coefficients for small values of nnn and kkk. For example:

    • To find (52)\binom{5}{2}(25​), look in the 5th row (counting from 0) and the 2nd position (counting from 0). The value is 101010.

    • To find (41)\binom{4}{1}(14​), look in the 4th row and the 1st position. The value is 444.

    Relationship Between Pascal’s Identity and Pascal’s Triangle

    Pascal’s Identity explains the recursive structure of Pascal's Triangle. Each entry in the triangle is generated by adding the two entries directly above it. This matches the recurrence relation given by Pascal's Identity:

    (nk)=(n−1k−1)+(n−1k)\binom{n}{k} = \binom{n-1}{k-1} + \binom{n-1}{k}(kn​)=(k−1n−1​)+(kn−1​)

    For example, consider the 4th row of Pascal’s Triangle: 1,3,3,11, 3, 3, 11,3,3,1. To verify Pascal’s Identity:

    • (31)=(20)+(21)=1+2=3\binom{3}{1} = \binom{2}{0} + \binom{2}{1} = 1 + 2 = 3(13​)=(02​)+(12​)=1+2=3,
    • (32)=(21)+(22)=2+1=3\binom{3}{2} = \binom{2}{1} + \binom{2}{2} = 2 + 1 = 3(23​)=(12​)+(22​)=2+1=3.

    This is consistent with the numbers in the 4th row of Pascal’s Triangle.

    Applications of Pascal’s Identity and Pascal’s Triangle

    1. Binomial Expansions: Pascal’s Triangle gives the coefficients for the expansion of binomials raised to any power. For example, the coefficients in the expansion of (x+y)5(x + y)^5(x+y)5 are found in the 5th row of Pascal's Triangle: 1,5,10,10,5,11, 5, 10, 10, 5, 11,5,10,10,5,1.

    2. Combinatorics: Pascal’s Identity and Pascal’s Triangle are widely used in counting problems, where you need to find how many ways there are to choose kkk items from a set of nnn items.

    3. Probability Theory: Binomial coefficients (and Pascal’s Triangle) are used in calculating probabilities in situations involving repeated trials (e.g., the binomial distribution).

    4. Recursive Algorithms: Pascal’s Identity is used in recursive algorithms to calculate binomial coefficients and in dynamic programming approaches to optimize such calculations.

    Conclusion

    Pascal’s Identity provides a recursive relationship for binomial coefficients, while Pascal’s Triangle is a convenient way to visualize and calculate those coefficients. Together, they form an essential tool for solving problems in combinatorics, algebra, and probability. Pascal’s Triangle allows you to quickly reference binomial coefficients, and Pascal’s Identity gives a deeper understanding of the relationships between those coefficients.

    Previous topic 48
    Binomial Coefficients
    Next topic 50
    Binomial Theorem

    Past Papers

    Open this section to load past papers

    Click on Show Past Papers to see past papers.
    On This Page
      Reading Stats
      Est. reading time8 min
      Word count1,438
      Code examples0
      DifficultyIntermediate