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    Math Deficiency - I
    MD-001
    Progress0 / 38 topics
    Topics
    1. Sets: Definition, Representation, and Operations2. Relation and Function: Graphical Transformation of Functions3. Properties of Functions4. Composition and Inverses of Functions5. Domain and Range of Functions6. Maximum and Minimum Values of Functions7. Increasing and Decreasing Functions8. Zeros and Intercepts of Functions9. Piecewise Functions10. Continuity and Discontinuity of Functions11. Polynomials and Rational Functions12. Polynomial Long Division and Synthetic Division13. Solution of Rational Functions14. Absolute Valued Functions and Their Properties15. Asymptotes: Horizontal, Vertical, and Oblique16. Exponential Functions and Their Properties17. Logarithmic Functions and Their Properties18. Systems of Equations: Two Equations and Two Unknowns19. Systems of Equations: Three Equations and Three Unknowns20. Matrix Algebra: Addition, Subtraction, and Multiplication21. Row Operations and Row Echelon Forms22. Augmented Matrices23. Determinant of Matrices: 2x2 and Higher Order24. Cramer's Rule25. Inverse Matrices26. Series and Sequences27. Trigonometry: Angles in Radians and Degrees28. Right Triangle Trigonometry29. Law of Cosines and Sines30. Area of a Triangle31. Graphs of Trigonometric Functions32. Graphs of Inverse Trigonometric Functions33. Basic Trigonometric Identities34. Trigonometric Equations35. General Form of a Conic: Parabolas, Circles, Ellipses, and Hyperbolas36. Degenerate Conics37. Polar and Parametric Equations38. Polar and Rectangular Coordinates
    MD-001›Right Triangle Trigonometry
    Math Deficiency - ITopic 28 of 38

    Right Triangle Trigonometry

    9 minread
    1,447words
    Intermediatelevel

    Right Triangle Trigonometry

    Right triangle trigonometry is a fundamental part of trigonometry that deals with the relationships between the angles and sides of right-angled triangles. In a right triangle, one of the angles is exactly 90∘90^\circ90∘, and the other two angles are complementary (they add up to 90∘90^\circ90∘).

    The primary focus of right triangle trigonometry is the use of trigonometric ratios to relate the sides of the triangle to its angles.

    1. Parts of a Right Triangle

    A right triangle has three sides:

    • Hypotenuse: The longest side of the triangle, opposite the right angle.
    • Opposite side: The side opposite the angle you're referring to (other than the right angle).
    • Adjacent side: The side next to the angle you're referring to (other than the right angle).

    For example, in a right triangle with an angle θ\thetaθ (other than the right angle), the sides are labeled as follows:

    • Hypotenuse: hhh
    • Opposite side to θ\thetaθ: ooo
    • Adjacent side to θ\thetaθ: aaa

    2. Trigonometric Ratios

    In right triangle trigonometry, we define the basic trigonometric functions as ratios of the sides of the triangle. These are:

    • Sine (sin):

      sin⁡(θ)=Opposite sideHypotenuse=oh\sin(\theta) = \frac{\text{Opposite side}}{\text{Hypotenuse}} = \frac{o}{h}sin(θ)=HypotenuseOpposite side​=ho​
    • Cosine (cos):

      cos⁡(θ)=Adjacent sideHypotenuse=ah\cos(\theta) = \frac{\text{Adjacent side}}{\text{Hypotenuse}} = \frac{a}{h}cos(θ)=HypotenuseAdjacent side​=ha​
    • Tangent (tan):

      tan⁡(θ)=Opposite sideAdjacent side=oa\tan(\theta) = \frac{\text{Opposite side}}{\text{Adjacent side}} = \frac{o}{a}tan(θ)=Adjacent sideOpposite side​=ao​
    • Cosecant (csc) (the reciprocal of sine):

      csc⁡(θ)=1sin⁡(θ)=ho\csc(\theta) = \frac{1}{\sin(\theta)} = \frac{h}{o}csc(θ)=sin(θ)1​=oh​
    • Secant (sec) (the reciprocal of cosine):

      sec⁡(θ)=1cos⁡(θ)=ha\sec(\theta) = \frac{1}{\cos(\theta)} = \frac{h}{a}sec(θ)=cos(θ)1​=ah​
    • Cotangent (cot) (the reciprocal of tangent):

      cot⁡(θ)=1tan⁡(θ)=ao\cot(\theta) = \frac{1}{\tan(\theta)} = \frac{a}{o}cot(θ)=tan(θ)1​=oa​

    These functions allow us to find unknown sides or angles in a right triangle when we have enough information.

    3. The Pythagorean Theorem

    The Pythagorean Theorem is a key principle in right triangle trigonometry. It states that in any right triangle:

    a2+o2=h2a^2 + o^2 = h^2a2+o2=h2

    Where:

    • aaa = adjacent side
    • ooo = opposite side
    • hhh = hypotenuse

    This theorem is used to find the length of one side of a right triangle if the lengths of the other two sides are known.

    Example: If a=3a = 3a=3 and o=4o = 4o=4, find hhh.

    32+42=h23^2 + 4^2 = h^232+42=h2 9+16=h29 + 16 = h^29+16=h2 h2=25h^2 = 25h2=25 h=5h = 5h=5

    4. Using Trigonometric Ratios to Solve Right Triangles

    To solve a right triangle using trigonometric ratios, we need to have either:

    • One angle and one side, or
    • Two sides of the triangle.

    Example 1: Given a right triangle with an angle θ=30∘\theta = 30^\circθ=30∘ and the hypotenuse h=10h = 10h=10, find the length of the opposite side ooo.

    Use the sine function:

    sin⁡(30∘)=oh\sin(30^\circ) = \frac{o}{h}sin(30∘)=ho​ sin⁡(30∘)=12(from trigonometric tables or a calculator)\sin(30^\circ) = \frac{1}{2} \quad \text{(from trigonometric tables or a calculator)}sin(30∘)=21​(from trigonometric tables or a calculator) 12=o10\frac{1}{2} = \frac{o}{10}21​=10o​

    Solving for ooo:

    o=12×10=5o = \frac{1}{2} \times 10 = 5o=21​×10=5

    So, the opposite side o=5o = 5o=5.

    Example 2: Given a right triangle with o=7o = 7o=7 and a=24a = 24a=24, find θ\thetaθ.

    Use the tangent function:

    tan⁡(θ)=oa\tan(\theta) = \frac{o}{a}tan(θ)=ao​ tan⁡(θ)=724\tan(\theta) = \frac{7}{24}tan(θ)=247​

    Now, to find θ\thetaθ, take the inverse tangent (or arctan):

    θ=tan⁡−1(724)\theta = \tan^{-1}\left(\frac{7}{24}\right)θ=tan−1(247​)

    Using a calculator:

    θ≈16.26∘\theta \approx 16.26^\circθ≈16.26∘

    5. Solving for Missing Angles

    When you are given the sides of a right triangle, you can use trigonometric functions to find the angles. For example, to find an angle θ\thetaθ using the tangent ratio:

    θ=tan⁡−1(oa)\theta = \tan^{-1}\left(\frac{o}{a}\right)θ=tan−1(ao​)

    Alternatively, you can use sine or cosine functions to find the angles:

    • θ=sin⁡−1(oh)\theta = \sin^{-1}\left(\frac{o}{h}\right)θ=sin−1(ho​)
    • θ=cos⁡−1(ah)\theta = \cos^{-1}\left(\frac{a}{h}\right)θ=cos−1(ha​)

    Example: Given a triangle with o=5o = 5o=5 and h=13h = 13h=13, find θ\thetaθ.

    Use the sine function:

    sin⁡(θ)=oh=513\sin(\theta) = \frac{o}{h} = \frac{5}{13}sin(θ)=ho​=135​ θ=sin⁡−1(513)\theta = \sin^{-1}\left(\frac{5}{13}\right)θ=sin−1(135​)

    Using a calculator:

    θ≈22.62∘\theta \approx 22.62^\circθ≈22.62∘

    6. Summary of Key Formulas

    • Sine: sin⁡(θ)=oh\sin(\theta) = \frac{o}{h}sin(θ)=ho​

    • Cosine: cos⁡(θ)=ah\cos(\theta) = \frac{a}{h}cos(θ)=ha​

    • Tangent: tan⁡(θ)=oa\tan(\theta) = \frac{o}{a}tan(θ)=ao​

    • Cosecant: csc⁡(θ)=1sin⁡(θ)=ho\csc(\theta) = \frac{1}{\sin(\theta)} = \frac{h}{o}csc(θ)=sin(θ)1​=oh​

    • Secant: sec⁡(θ)=1cos⁡(θ)=ha\sec(\theta) = \frac{1}{\cos(\theta)} = \frac{h}{a}sec(θ)=cos(θ)1​=ah​

    • Cotangent: cot⁡(θ)=1tan⁡(θ)=ao\cot(\theta) = \frac{1}{\tan(\theta)} = \frac{a}{o}cot(θ)=tan(θ)1​=oa​

    • Pythagorean Theorem: a2+o2=h2a^2 + o^2 = h^2a2+o2=h2


    Summary

    Right triangle trigonometry provides powerful methods for solving problems involving right-angled triangles by using trigonometric ratios (sine, cosine, tangent, etc.) and the Pythagorean Theorem. With these tools, we can find missing sides or angles in right triangles when sufficient information is provided. Understanding how to apply these formulas is essential for solving problems in geometry, physics, and engineering.

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    Trigonometry: Angles in Radians and Degrees
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    Law of Cosines and Sines

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