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    Tools for Quantitative Reasoning
    MATH2118
    Progress0 / 27 topics
    Topics
    1. Logic, Logical and Critical Reasoning: Introduction and importance of logic2. Inductive, deductive and abductive approaches of reasoning3. Propositions4. Argutnents (valid and invalid5. Logical connectives6. Truth tables and propositional equivalences7. Logical fallacies8. Venn Diagrams9. Predicates and quantifiers10. Quantitative reasoning exercises using logical reasoning concepts and techniques11. Mathematical Modeling and Analyses12. Introduction to deterministic models13. Use of linear functions for modeling in real-world situations14. Modeling with the system of linear equations and their solutions15. Elementary introduction to derivatives in mathematical modeling16. Linear and exponential growth and decay models17. Quantitative reasoning exercises using mathematical modeling18. Statistical Modeling and Analyses19. Introduction to probabilistic models20. Bivariate analysis, scatter plots21. Simple linear regression model and correlation analysis22. Basics of estimation and confidence interval23. Testing of hypothesis24. z-test25. t-test26. Statistical inference in decision making27. Quantitative reasoning exercises using statistical modeling
    MATH2118›Quantitative reasoning exercises using mathematical modeling
    Tools for Quantitative ReasoningTopic 17 of 27

    Quantitative reasoning exercises using mathematical modeling

    8 minread
    1,321words
    Intermediatelevel

    Quantitative reasoning exercises using mathematical modeling help develop analytical skills by applying mathematical concepts to solve real-world problems. Here are several exercises that incorporate different types of mathematical modeling, along with solutions or guiding steps.

    Exercise 1: Linear Cost and Revenue Model

    Problem: A company produces and sells widgets. The cost to produce xxx widgets is given by the function C(x)=50x+200C(x) = 50x + 200C(x)=50x+200 (where 50isthevariablecostperwidgetand50 is the variable cost per widget and 50isthevariablecostperwidgetand200 is fixed costs). The selling price per widget is $80.

    1. Write the revenue function R(x)R(x)R(x).
    2. Determine the number of widgets xxx that must be sold to break even.

    Solution Steps:

    1. Revenue Function:

      R(x)=80xR(x) = 80xR(x)=80x
    2. Break-even Point: Set the revenue equal to the cost:

      R(x)=C(x)80x=50x+200R(x) = C(x) \\ 80x = 50x + 200R(x)=C(x)80x=50x+200 30x=200x=20030≈6.6730x = 200 \\ x = \frac{200}{30} \approx 6.6730x=200x=30200​≈6.67

      Since you can’t sell a fraction of a widget, the company must sell at least 7 widgets to break even.

    Exercise 2: Exponential Growth Model

    Problem: A bacteria culture starts with 200 bacteria and doubles every 3 hours.

    1. Write a model for the population of bacteria P(t)P(t)P(t) after ttt hours.
    2. How many bacteria will there be after 12 hours?

    Solution Steps:

    1. Population Model: Since the population doubles every 3 hours:

      P(t)=200⋅2t3P(t) = 200 \cdot 2^{\frac{t}{3}}P(t)=200⋅23t​
    2. Population After 12 Hours:

      P(12)=200⋅2123=200⋅24=200⋅16=3200P(12) = 200 \cdot 2^{\frac{12}{3}} = 200 \cdot 2^4 = 200 \cdot 16 = 3200P(12)=200⋅2312​=200⋅24=200⋅16=3200

      There will be 3,200 bacteria after 12 hours.

    Exercise 3: Linear Programming for Optimization

    Problem: A farmer has 100 acres of land to plant crops. Each acre of corn requires 2 hours of labor and yields 200profit,whileeachacreofsoybeansrequires4hoursoflaborandyields200 profit, while each acre of soybeans requires 4 hours of labor and yields 200profit,whileeachacreofsoybeansrequires4hoursoflaborandyields300 profit. The farmer has 240 hours of labor available.

    1. Formulate the objective function for profit maximization.
    2. Identify the constraints.
    3. Determine how many acres of each crop to plant to maximize profit.

    Solution Steps:

    1. Variables: Let xxx be the acres of corn and yyy be the acres of soybeans.

    2. Objective Function: Maximize profit PPP:

      P=200x+300yP = 200x + 300yP=200x+300y
    3. Constraints:

      • Land constraint: x+y≤100x + y \leq 100x+y≤100
      • Labor constraint: 2x+4y≤2402x + 4y \leq 2402x+4y≤240
      • Non-negativity: x≥0,y≥0x \geq 0, y \geq 0x≥0,y≥0
    4. Solving the System: Use graphical methods or a linear programming tool to find the optimal solution.

    Exercise 4: Population Decay Model

    Problem: A certain radioactive substance has a half-life of 10 years. If you start with 80 grams of the substance, write an equation to model the amount remaining after ttt years and calculate how much remains after 30 years.

    Solution Steps:

    1. Decay Model: The amount remaining after ttt years can be modeled as:

      N(t)=N0⋅(12)t10N(t) = N_0 \cdot \left(\frac{1}{2}\right)^{\frac{t}{10}}N(t)=N0​⋅(21​)10t​

      where N0=80N_0 = 80N0​=80 grams.

    2. Remaining After 30 Years:

      N(30)=80⋅(12)3010=80⋅(12)3=80⋅18=10N(30) = 80 \cdot \left(\frac{1}{2}\right)^{\frac{30}{10}} = 80 \cdot \left(\frac{1}{2}\right)^3 = 80 \cdot \frac{1}{8} = 10N(30)=80⋅(21​)1030​=80⋅(21​)3=80⋅81​=10

      After 30 years, 10 grams of the substance will remain.

    Exercise 5: System of Equations in Economics

    Problem: A coffee shop sells coffee for 5percupandpastriesfor5 per cup and pastries for 5percupandpastriesfor3 each. On a busy day, the shop sells 150 items for a total of $600.

    1. Set up a system of equations to represent the situation.
    2. Solve the system to find out how many cups of coffee and pastries were sold.

    Solution Steps:

    1. Variables: Let ccc be the number of cups of coffee and ppp be the number of pastries.

    2. Equations:

      • Total items: c+p=150c + p = 150c+p=150 (1)
      • Total revenue: 5c+3p=6005c + 3p = 6005c+3p=600 (2)
    3. Solving the System: From equation (1), express ppp:

      p=150−cp = 150 - cp=150−c

      Substitute into equation (2):

      5c+3(150−c)=6005c+450−3c=6002c=150c=755c + 3(150 - c) = 600 \\ 5c + 450 - 3c = 600 \\ 2c = 150 \\ c = 755c+3(150−c)=6005c+450−3c=6002c=150c=75

      Then substitute back to find ppp:

      p=150−75=75p = 150 - 75 = 75p=150−75=75

      The shop sold 75 cups of coffee and 75 pastries.

    Conclusion

    These exercises demonstrate how mathematical modeling can be used to analyze various scenarios involving growth, decay, optimization, and systems of equations. By engaging with these problems, you can strengthen your quantitative reasoning skills and apply mathematical concepts to real-world situations.

    Previous topic 16
    Linear and exponential growth and decay models
    Next topic 18
    Statistical Modeling and Analyses

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