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    Applied Physics
    GE-169
    Progress0 / 45 topics
    Topics
    1. Electric Force and Its Applications2. Conservation of Charge3. Charge Quantization4. Electric Fields Due to Point Charge and Lines of Force5. Electric Fields: Ring of Charge and Disk of Charge6. A Point Charge in an Electric Field7. Dipole in an Electric Field8. Flux of a Vector Field9. Flux of an Electric Field10. Gauss’ Law and Its Applications11. Spherically Symmetric Charge Distribution12. Charge Isolated Conductor13. Electric Potential Energy14. Electric Potentials and Related Problems15. Calculating Potential from the Field16. Potential Due to Point and Continuous Charge Distribution17. Potential Due to a Dipole18. Equipotential Surfaces19. Calculating the Field from the Potential20. Electric Current and Current Density21. Resistance, Resistivity, and Conductivity22. Ohm's Law and Its Applications23. The Hall Effect24. Magnetic Force on a Current25. The Biot-Savart Law26. Line of Magnetic Field (B)27. Two Parallel Conductors28. Ampere's Law29. Solenoids and Toroids30. Faraday's Experiments and Law of Induction31. Lenz's Law32. Motional EMF33. Induced Electric Fields34. The Basic Equations of Electromagnetism35. Induced Magnetic Fields36. The Displacement Current37. Reflection and Refraction of Light Waves38. Total Internal Reflection39. Two Source Interference40. Double-Slit Interference and Related Problems41. Interference from Thin Films42. Diffraction and Wave Theory43. Single-Slit Diffraction and Related Problems44. Polarization of Electromagnetic Waves45. Polarizing Sheets and Related Problems
    GE-169›Electric Fields: Ring of Charge and Disk of Charge
    Applied PhysicsTopic 5 of 45

    Electric Fields: Ring of Charge and Disk of Charge

    11 minread
    1,928words
    Intermediatelevel

    Electric Fields: Ring of Charge and Disk of Charge

    The electric field produced by a ring of charge or a disk of charge is more complex than that of a point charge, as the charge distribution is not concentrated at a single point. In these cases, the electric field at a point in space is determined by the contributions of all the small charge elements in the ring or disk. Let's explore how to calculate the electric fields produced by a ring of charge and a disk of charge, along with their properties.


    1. Electric Field Due to a Ring of Charge

    a) Setup and Symmetry

    Consider a thin ring of charge with a total charge QQQ uniformly distributed along the circumference. The radius of the ring is RRR, and we wish to find the electric field at a point along the axis of the ring, at a distance zzz from the center of the ring.

    • Let the charge QQQ be distributed uniformly along the circumference of the ring.
    • The point where we want to calculate the electric field lies along the axis that is perpendicular to the plane of the ring (the z-axis).

    b) Calculation of the Electric Field

    To calculate the electric field at a point on the axis, consider a small element of charge dqdqdq on the ring. This small charge element creates an electric field at the point of interest. Since the ring is symmetrical, we can calculate the field by considering the contributions from all small charge elements.

    • The magnitude of the electric field due to a small charge element dqdqdq at a point located at distance zzz from the center of the ring is given by Coulomb’s Law:
    dE=ke dqr2dE = \frac{k_e \, dq}{r^2}dE=r2ke​dq​

    Where:

    • kek_eke​ is Coulomb's constant (8.99×109 N m2C−28.99 \times 10^9 \, \text{N m}^2 \text{C}^{-2}8.99×109N m2C−2),
    • rrr is the distance from the charge element dqdqdq to the point where the field is calculated.

    For a ring of charge, the distance rrr from each element to the point on the axis is:

    r=R2+z2r = \sqrt{R^2 + z^2}r=R2+z2​

    Where RRR is the radius of the ring, and zzz is the distance from the center of the ring along the axis.

    Now, we need to determine the direction of the electric field. Due to symmetry, the horizontal (radial) components of the electric field from each charge element will cancel out, and only the vertical components (along the z-axis) will contribute to the net field at the point.

    • The vertical component of the electric field due to each charge element is:
    dEz=dEcos⁡θdE_z = dE \cos \thetadEz​=dEcosθ

    Where θ\thetaθ is the angle between the position vector of the charge element and the axis of the ring. Using trigonometry, we have:

    cos⁡θ=zR2+z2\cos \theta = \frac{z}{\sqrt{R^2 + z^2}}cosθ=R2+z2​z​

    Thus, the vertical component of the electric field from a charge element dqdqdq is:

    dEz=ke dq z(R2+z2)3/2dE_z = \frac{k_e \, dq \, z}{(R^2 + z^2)^{3/2}}dEz​=(R2+z2)3/2ke​dqz​

    c) Total Electric Field Along the Axis

    To get the total electric field along the axis, we integrate over the entire ring. Since the charge is uniformly distributed, we can express the total charge QQQ as dq=Q2πR dθdq = \frac{Q}{2 \pi R} \, d\thetadq=2πRQ​dθ, where dθd\thetadθ is a small angle subtended by each charge element at the center of the ring.

    The total electric field along the z-axis is:

    Ez=∫02πke z dq(R2+z2)3/2E_z = \int_0^{2\pi} \frac{k_e \, z \, dq}{(R^2 + z^2)^{3/2}}Ez​=∫02π​(R2+z2)3/2ke​zdq​

    Substituting dq=Q2πRdθdq = \frac{Q}{2 \pi R} d\thetadq=2πRQ​dθ, we get:

    Ez=keQz(R2+z2)3/2E_z = \frac{k_e Q z}{(R^2 + z^2)^{3/2}}Ez​=(R2+z2)3/2ke​Qz​

    So, the total electric field due to a ring of charge at a point on its axis at a distance zzz from the center is:

    Ez=keQz(R2+z2)3/2E_z = \frac{k_e Q z}{(R^2 + z^2)^{3/2}}Ez​=(R2+z2)3/2ke​Qz​

    d) Key Insights

    • The electric field along the axis of a ring of charge depends on both the total charge QQQ and the distance from the ring zzz.
    • The field is strongest when zzz is small (close to the center of the ring), but it decreases as zzz increases.
    • The electric field is directed along the axis of the ring (the z-axis), and it decreases in magnitude with increasing distance from the ring.

    2. Electric Field Due to a Disk of Charge

    a) Setup and Symmetry

    Consider a uniformly charged disk with a total charge QQQ distributed over its surface. The disk has radius RRR, and we want to calculate the electric field at a point located along the axis of the disk, at a distance zzz from its center.

    • The total charge QQQ is uniformly distributed over the surface of the disk.
    • The disk has radius RRR, and we are calculating the electric field along its axis, which is perpendicular to the disk.

    b) Electric Field Due to a Small Ring Element of the Disk

    To find the total electric field, consider the disk as a collection of concentric rings of charge. Each ring has radius rrr and a small width drdrdr, and the charge dqdqdq on the ring is:

    dq=σ 2πr drdq = \sigma \, 2\pi r \, drdq=σ2πrdr

    Where:

    • σ=QπR2\sigma = \frac{Q}{\pi R^2}σ=πR2Q​ is the surface charge density of the disk, i.e., the charge per unit area.

    The electric field at a distance zzz along the axis due to a small ring of charge is similar to the case of the ring of charge, but with a different integration limit for the radius rrr.

    The electric field due to a ring of charge of radius rrr at a point on the axis is:

    dEz=ke dq z(r2+z2)3/2dE_z = \frac{k_e \, dq \, z}{(r^2 + z^2)^{3/2}}dEz​=(r2+z2)3/2ke​dqz​

    Substituting dq=σ 2πr drdq = \sigma \, 2 \pi r \, drdq=σ2πrdr into this expression:

    dEz=ke σ 2πr z dr(r2+z2)3/2dE_z = \frac{k_e \, \sigma \, 2 \pi r \, z \, dr}{(r^2 + z^2)^{3/2}}dEz​=(r2+z2)3/2ke​σ2πrzdr​

    c) Total Electric Field Along the Axis

    To get the total electric field, we integrate the expression for dEzdE_zdEz​ over the radius rrr from 0 to RRR:

    Ez=∫0Rke σ 2πr z dr(r2+z2)3/2E_z = \int_0^R \frac{k_e \, \sigma \, 2 \pi r \, z \, dr}{(r^2 + z^2)^{3/2}}Ez​=∫0R​(r2+z2)3/2ke​σ2πrzdr​

    This integral can be solved (though it is a bit tedious), and the result is:

    Ez=keQzR2(R2+z2)1/2E_z = \frac{k_e Q z}{R^2 (R^2 + z^2)^{1/2}}Ez​=R2(R2+z2)1/2ke​Qz​

    d) Key Insights for the Disk of Charge

    • The electric field due to a disk of charge is strongest at the center of the disk and decreases as we move farther from the disk along its axis.
    • For a point very far from the disk (large zzz), the disk behaves like a point charge, and the electric field falls off as 1z2\frac{1}{z^2}z21​, similar to the field of a point charge.
    • Near the center of the disk, the electric field is directed along the axis of the disk (the z-axis), and the field is stronger near the center and weaker farther away.

    3. Summary of Electric Fields Due to Ring and Disk of Charge

    Ring of Charge:

    • The electric field along the axis of a ring of charge is given by:
    Ez=keQz(R2+z2)3/2E_z = \frac{k_e Q z}{(R^2 + z^2)^{3/2}}Ez​=(R2+z2)3/2ke​Qz​
    • The field decreases as you move farther away from the ring along the axis.

    Disk of Charge:

    • The electric field along the axis of a uniformly charged disk is:
    Ez=keQzR2(R2+z2)1/2E_z = \frac{k_e Q z}{R^2 (R^2 + z^2)^{1/2}}Ez​=R2(R2+z2)1/2ke​Qz​
    • The electric field is strongest at the center of the disk and decreases with distance along the axis.

    These fields are crucial for understanding charge distributions in a variety of physical situations, from simple setups to complex configurations in physics and engineering applications.

    Previous topic 4
    Electric Fields Due to Point Charge and Lines of Force
    Next topic 6
    A Point Charge in an Electric Field

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